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7p^2-4p-75=0
a = 7; b = -4; c = -75;
Δ = b2-4ac
Δ = -42-4·7·(-75)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-46}{2*7}=\frac{-42}{14} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+46}{2*7}=\frac{50}{14} =3+4/7 $
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